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Edexcel A-Level Physics: Thermodynamics

6 exam-style questions with full mark schemes and model answers. Write your own answer and the AI examiner marks it against the mark scheme.

Learn this properly: Internal Energy
Question 16 marksExplain

A solid block of pure ice at 10 °C-10\ \text{°C}10 °C is heated at a steady rate by an electrical heater until it has been completely converted into water vapour. A datalogger records the temperature of the sample throughout, producing a heating curve with two horizontal sections (plateaux) separated by sloping sections.

Explain, in terms of the kinetic and potential energies of the molecules, why the temperature rises during the sloping sections but stays constant during the two plateaux, even though energy is supplied to the sample at a constant rate throughout.

(6 marks)

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Question 26 marksCalculate

A laboratory heater is used to convert a 0.25 kg0.25\ \text{kg}0.25 kg block of ice, initially at 0 °C0\ \text{°C}0 °C, completely into steam at 100 °C100\ \text{°C}100 °C. The process happens in three stages: the ice melts to water at 0 °C0\ \text{°C}0 °C, the water is then warmed to 100 °C100\ \text{°C}100 °C, and finally the water is boiled away to steam at 100 °C100\ \text{°C}100 °C. Assume no energy is lost to the surroundings.

QuantityValue
Mass of sample, mmm0.25 kg
Specific latent heat of fusion of ice, LfL_fLf3.34×105 J kg13.34 \times 10^{5}\ \text{J kg}^{-1}3.34×105 J kg1
Specific heat capacity of water, ccc4200 J kg1 K14200\ \text{J kg}^{-1}\ \text{K}^{-1}4200 J kg1 K1
Specific latent heat of vaporisation of water, LvL_vLv2.26×106 J kg12.26 \times 10^{6}\ \text{J kg}^{-1}2.26×106 J kg1

(a) Calculate the energy needed to melt the ice into water at 0 °C0\ \text{°C}0 °C. (2 marks)

(b) Calculate the energy needed to warm that water from 0 °C0\ \text{°C}0 °C to 100 °C100\ \text{°C}100 °C. (2 marks)

(c) Calculate the energy needed to boil the water into steam at 100 °C100\ \text{°C}100 °C, and hence state the total energy supplied across all three stages. (2 marks)

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Question 35 marksDetermine

A fixed mass of gas is slowly compressed in a sealed syringe held in a water bath at a constant temperature. For each setting, the pressure ppp and the volume VVV of the trapped gas are recorded. One volume reading was not taken.

Pressure ppp / kPa100120150200240
Volume VVV / cm³24.020.016.010.0

(a) By calculating a suitable quantity for the four complete readings, show that the data are consistent with Boyle's law, and state the two conditions Boyle's law requires. (3 marks)

(b) Use Boyle's law to determine the missing volume at a pressure of 200 kPa200\ \text{kPa}200 kPa. (2 marks)

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Question 45 marksCalculate

A scuba diver's air cylinder has an internal volume of 12 L12\ \text{L}12 L and is filled with compressed air to a pressure of 1.8×107 Pa1.8 \times 10^{7}\ \text{Pa}1.8×107 Pa at a temperature of 17 °C17\ \text{°C}17 °C. The compressed air may be treated as an ideal gas.

Take the molar gas constant R=8.31 J mol1 K1R = 8.31\ \text{J mol}^{-1}\ \text{K}^{-1}R=8.31 J mol1 K1 and the Avogadro constant NA=6.02×1023 mol1N_A = 6.02 \times 10^{23}\ \text{mol}^{-1}NA=6.02×1023 mol1.

(a) Calculate the amount of gas (in moles) inside the cylinder. (3 marks)

(b) Hence calculate the number of gas molecules inside the cylinder. (2 marks)

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Question 54 marksCalculate

Nitrogen gas in a sealed flask is at a temperature of 300 K300\ \text{K}300 K. A single nitrogen molecule has a mass of 4.65×1026 kg4.65 \times 10^{-26}\ \text{kg}4.65×1026 kg. The gas may be treated as ideal.

Take the Boltzmann constant k=1.38×1023 J K1k = 1.38 \times 10^{-23}\ \text{J K}^{-1}k=1.38×1023 J K1.

(a) Calculate the mean (random) translational kinetic energy of a nitrogen molecule at this temperature. (2 marks)

(b) Hence calculate the root-mean-square (r.m.s.) speed of the nitrogen molecules. (2 marks)

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Question 63 marksDefine and state

The behaviour of a substance can be described in terms of the energies of its molecules.

(a) Define the internal energy of a system. (2 marks)

(b) State what is meant by absolute zero in terms of the internal energy of a substance. (1 mark)

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