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AQA GCSE Maths: Angles, Polygons and Geometric Reasoning

6 exam-style questions with full mark schemes and model answers. Write your own answer and the AI examiner marks it against the mark scheme.

Question 15 marksWork out

AAA, BBB, CCC and DDD are four points on the circumference of a circle with centre OOO. BDBDBD is a diameter of the circle. The angle DBC=32\angle DBC = 32^{\circ}DBC=32, and the angle ADB=47\angle ADB = 47^{\circ}ADB=47.

(a) Write down, with a reason, the size of BCD\angle BCDBCD. (2 marks)

(b) Work out the size of BDC\angle BDCBDC, giving a reason. (2 marks)

(c) Work out the size of ABD\angle ABDABD. (1 mark)

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Question 24 marksWork out

The interior angle of a regular polygon is 156156^{\circ}156.

(a) Work out the number of sides of the polygon. (3 marks)

(b) Write down the sum of the interior angles of this polygon. (1 mark)

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Question 34 marksWork out

Two straight lines PQPQPQ and RSRSRS are parallel. A straight line crosses PQPQPQ at the point XXX and crosses RSRSRS at the point YYY. At XXX, on the upper side, the angle between the crossing line and XQXQXQ (measured towards QQQ) is 3x+103x + 103x+10 degrees. At YYY, on the lower side, the co-interior (allied) angle between the crossing line and YSYSYS is 2x+302x + 302x+30 degrees.

Work out the value of xxx, giving reasons for each step of your working. (4 marks)

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Question 43 marksWork out

Triangle ABCABCABC and triangle PQRPQRPQR are mathematically similar. In triangle ABCABCABC, AB=6AB = 6AB=6 cm and BC=9BC = 9BC=9 cm. In triangle PQRPQRPQR, the side PQPQPQ corresponds to ABABAB and PQ=15PQ = 15PQ=15 cm. The side QRQRQR corresponds to BCBCBC.

(a) Work out the length of QRQRQR. (2 marks)

(b) In triangle ABCABCABC, the angle ABC=52\angle ABC = 52^{\circ}ABC=52. Write down the size of the corresponding angle PQR\angle PQRPQR. (1 mark)

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Question 52 marksWork out

In triangle ABCABCABC, the side ABABAB is extended beyond BBB to a point DDD. The interior angle BAC=64\angle BAC = 64^{\circ}BAC=64 and the interior angle ACB=51\angle ACB = 51^{\circ}ACB=51. Work out the size of the exterior angle CBD\angle CBDCBD, giving a reason. (2 marks)

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Question 61 markWork out

Work out the size of one exterior angle of a regular hexagon. (1 mark)

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