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A complex ion consists of a central metal ion surrounded by ligands. Ligands are molecules or ions that donate a lone pair of electrons to the metal ion, forming a coordinate (dative covalent) bond. The study of complex ions is a central topic in transition metal chemistry and appears extensively at A-Level.
Ligands are classified by the number of coordinate bonds they can form with the central metal ion:
These donate one lone pair and form one coordinate bond per ligand:
| Ligand | Formula | Lone Pair Donor | Charge |
|---|---|---|---|
| Water | H₂O | O | 0 |
| Ammonia | NH₃ | N | 0 |
| Chloride | Cl⁻ | Cl | −1 |
| Cyanide | CN⁻ | C | −1 |
| Hydroxide | OH⁻ | O | −1 |
| Thiocyanate | SCN⁻ | S or N | −1 |
| Carbon monoxide | CO | C | 0 |
Exam note: Thiocyanate (SCN⁻) is an ambidentate ligand — it can bond through either S or N. When it bonds through S, it is thiocyanato; through N, it is isothiocyanato. At A-Level, just know it can bond through either end.
These donate two lone pairs from different atoms and form two coordinate bonds per ligand:
| Ligand | Formula | Donor Atoms |
|---|---|---|
| Ethane-1,2-diamine (en) | H₂NCH₂CH₂NH₂ | Two N atoms |
| Ethanedioate (oxalate) | C₂O₄²⁻ | Two O atoms |
The name "bidentate" means "two-toothed" — the ligand grips the metal ion at two points, like a crab's claw.
These donate more than two lone pairs and form multiple coordinate bonds:
The shape of a complex depends on the coordination number:
Six ligands arranged around the metal ion at 90° bond angles. This is the most common geometry.
Examples:
Four ligands arranged at approximately 109.5° bond angles. Common with larger ligands such as Cl⁻.
Examples:
Four ligands arranged in a plane at 90° bond angles. Less common but important for certain metals (especially Pt²⁺ and Ni²⁺ with strong-field ligands).
Examples:
Two ligands arranged at 180°.
Examples:
flowchart TD
A["Coordination Number"] --> B{"Number?"}
B -->|"6"| C["Octahedral<br>90° bond angles<br>e.g. [Fe(H₂O)₆]²⁺"]
B -->|"4"| D{"Ligand type?"}
D -->|"Large ligands (Cl⁻)"| E["Tetrahedral<br>109.5° bond angles<br>e.g. [CoCl₄]²⁻"]
D -->|"Strong-field, Pt/Ni"| F["Square Planar<br>90° bond angles<br>e.g. [Pt(NH₃)₂Cl₂]"]
B -->|"2"| G["Linear<br>180° bond angle<br>e.g. [Ag(NH₃)₂]⁺"]
Complex ion naming follows systematic rules:
| Complex | Name | Working for Oxidation State |
|---|---|---|
| [Cu(H₂O)₆]²⁺ | Hexaaquacopper(II) | Cu + 6(0) = +2, so Cu = +2 |
| [CoCl₄]²⁻ | Tetrachlorocobaltate(II) | Co + 4(−1) = −2, so Co = +2 |
| [Cr(NH₃)₆]³⁺ | Hexaamminechromium(III) | Cr + 6(0) = +3, so Cr = +3 |
| [Fe(CN)₆]⁴⁻ | Hexacyanoferrate(II) | Fe + 6(−1) = −4, so Fe = +2 |
| [Ag(NH₃)₂]⁺ | Diamminesilver(I) | Ag + 2(0) = +1, so Ag = +1 |
Key detail: For anionic complexes, the metal takes the Latin name with an "-ate" suffix: iron → ferrate, copper → cuprate, cobalt → cobaltate, chromium → chromate. For cationic or neutral complexes, the standard English name is used.
Square planar and octahedral complexes with two different types of ligand can show cis-trans (geometric) isomerism.
In the square planar complex [Pt(NH₃)₂Cl₂]:
The two isomers have different physical and biological properties despite having the same molecular formula. Cisplatin works by binding to DNA and preventing cell division; the spatial arrangement of the chloride ligands is critical for this binding.
Octahedral complexes with three bidentate ligands (e.g., [Ni(en)₃]²⁺) can show optical isomerism. The two mirror-image forms are non-superimposable and rotate plane-polarised light in opposite directions. This type of isomerism is tested at A-Level.
When bidentate or multidentate ligands replace monodentate ligands, the resulting chelated complex is more stable. This is called the chelate effect.
For example: [Ni(H₂O)₆]²⁺ + 3en → [Ni(en)₃]²⁺ + 6H₂O
Three bidentate en ligands replace six monodentate water ligands. The coordination number remains 6, but the chelated complex is significantly more stable.
The chelate effect is primarily an entropy-driven phenomenon. In the reaction above:
The number of species in solution increases from 4 to 7, so disorder (entropy) increases. The positive entropy change (ΔS > 0) makes ΔG more negative, favouring the chelated product.
This can be quantified: ΔG = ΔH − TΔS. Even if ΔH is approximately zero (similar bond strengths), the large positive TΔS term ensures ΔG is negative.
Question: Name the complex [Cr(NH₃)₄Cl₂]⁺ and determine the oxidation state of chromium.
Answer:
Complex ions consist of a central metal ion bonded to ligands via coordinate bonds. Ligands can be monodentate, bidentate, or multidentate. Common shapes include octahedral (6), tetrahedral (4), square planar (4), and linear (2). The chelate effect makes complexes with polydentate ligands more stable, driven by an entropy increase. Naming follows systematic rules with ligand prefixes, ligand names in alphabetical order, metal name (with "-ate" for anions), and oxidation state in Roman numerals.
Edexcel 9CH0 specification Topic 15 — Transition Metals, sub-topic 15.2 covers ligands as electron-pair donors (Lewis bases), monodentate / bidentate / polydentate ligands (H₂O, NH₃, Cl⁻, CN⁻, OH⁻; en (1,2-diaminoethane); EDTA⁴⁻), coordination number, common shapes (octahedral, tetrahedral, square planar), and ligand-exchange reactions in aqueous transition-metal chemistry (refer to the official specification document for exact wording). Examined in Paper 1 (9CH0/01) and Paper 3 (9CH0/03) through CP16. Synoptic links to Topic 2 (Bonding and Structure: VSEPR) for shapes, Topic 13 (Energetics II) for chelate effect (entropy), and to lesson 7 (colour) and lesson 9 (qualitative analysis).
Question (8 marks):
(a) Define a ligand and explain the difference between monodentate, bidentate and polydentate ligands. Give one example of each. (3)
(b) When excess concentrated NH₃ is added stepwise to aqueous CuSO₄, the pale blue solution becomes deep blue. Write the equations for the ligand-exchange steps and explain the colour change in terms of the species present. (3)
(c) Predict the shape of [Ni(CN)₄]²⁻ and [NiCl₄]²⁻, justifying any difference. (2)
Solution with mark scheme:
(a) Ligand = species (atom, ion or molecule) that donates a lone pair of electrons into an empty orbital of a transition-metal cation, forming a dative covalent (coordinate) bond.
B1 — definition.
B1 — three types correctly distinguished.
B1 — at least one valid example for each.
(b) Step 1 — initial complex.
[Cu(H₂O)₆]²⁺(aq) — pale blue (octahedral, six water ligands).
Step 2 — partial ligand exchange.
[Cu(H₂O)₆]²⁺ + 4NH₃ ⇌ [Cu(NH₃)₄(H₂O)₂]²⁺ + 4H₂O
Ammonia replaces only the four equatorial water ligands; the two axial waters remain (the axial bonds are longer due to Jahn–Teller distortion of d⁹).
M1 — equation correct, four NH₃ in, four H₂O out.
M1 — colour change: pale blue → deep royal blue. The deeper colour arises because NH₃ produces a larger ligand-field splitting Δ_oct than H₂O (NH₃ is higher in the spectrochemical series), so the d–d absorption shifts to higher energy (shorter wavelength), making the complementary colour more intensely blue.
A1 — note the formation of pale blue intermediate gelatinous Cu(OH)₂ precipitate at low NH₃ concentration before redissolving in excess as [Cu(NH₃)₄(H₂O)₂]²⁺.
(c) [Ni(CN)₄]²⁻ — square planar. CN⁻ is a strong-field ligand (high in spectrochemical series); the d⁸ configuration of Ni²⁺ in a strong field undergoes pairing with two electrons in the higher-energy d_x²−y² orbital depopulated, favouring square planar.
[NiCl₄]²⁻ — tetrahedral. Cl⁻ is a weak-field ligand; ligand-field stabilisation does not favour square planar over tetrahedral; the larger Cl⁻ also creates steric pressure favouring tetrahedral 4-coordinate geometry.
M1 — both shapes correct.
A1 — justified by ligand-field strength (CN⁻ vs Cl⁻ in spectrochemical series).
Total: 8 marks (M3 A2 B3).
Question (6 marks): Excess concentrated HCl is added to a solution containing [Cu(H₂O)₆]²⁺.
(a) Write the equation for the ligand-exchange reaction. (1)
(b) Predict the shape and coordination number of the product. State and explain the colour change. (3)
(c) Discuss why the chloride product has a different coordination number from the original aqua complex. (2)
Mark scheme decomposition by AO:
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