You are viewing a free preview of this lesson.
Subscribe to unlock all 10 lessons in this course and every other course on LearningBro.
This lesson covers isotopes and how to calculate relative atomic mass — as required by the Edexcel GCSE Chemistry specification (1CH0), Topic 1: Key Concepts in Chemistry. You need to understand what isotopes are, why they have the same chemical properties, and be able to calculate relative atomic mass from isotopic abundance data.
Isotopes are atoms of the same element that have the same number of protons but different numbers of neutrons. This means they have the same atomic number but different mass numbers.
Exam Tip: When explaining why isotopes have the same chemical properties, you MUST say it is because they have the same number of electrons (or the same electron configuration). Chemical properties depend on electrons, not on neutrons. This is a very commonly examined point.
| Isotope | Protons | Neutrons | Mass Number | Electron Configuration |
|---|---|---|---|---|
| Carbon-12 (¹²C) | 6 | 6 | 12 | 2, 4 |
| Carbon-13 (¹³C) | 6 | 7 | 13 | 2, 4 |
| Carbon-14 (¹⁴C) | 6 | 8 | 14 | 2, 4 |
All three isotopes have 6 protons (because they are all carbon) and 6 electrons (same chemical properties). They differ only in the number of neutrons.
| Isotope | Protons | Neutrons | Mass Number |
|---|---|---|---|
| Chlorine-35 (³⁵Cl) | 17 | 18 | 35 |
| Chlorine-37 (³⁷Cl) | 17 | 20 | 37 |
Chlorine has two stable isotopes. In a natural sample of chlorine, approximately 75% of atoms are ³⁵Cl and 25% are ³⁷Cl.
Hydrogen is unique in that its isotopes have individual names:
| Isotope | Name | Protons | Neutrons | Mass Number |
|---|---|---|---|---|
| ¹H | Hydrogen (protium) | 1 | 0 | 1 |
| ²H | Deuterium | 1 | 1 | 2 |
| ³H | Tritium | 1 | 2 | 3 |
Most elements exist as a mixture of isotopes in nature. The relative atomic mass (Aᵣ) of an element is the weighted average of the mass numbers of all its naturally occurring isotopes, taking into account their relative abundance (how common each isotope is).
Relative atomic mass (Aᵣ) is the weighted mean mass of an atom of an element compared to one-twelfth of the mass of a carbon-12 atom.
This is why relative atomic mass values on the periodic table are often not whole numbers — they are averages. For example, the Aᵣ of chlorine is 35.5, not 35 or 37.
Exam Tip: In the Edexcel exam, if you are asked to define relative atomic mass, say it is the "weighted mean mass of an atom of an element compared to 1/12th of the mass of a carbon-12 atom." The word weighted is essential — it means the more abundant isotopes contribute more to the average.
To calculate the Aᵣ from isotopic abundance data, use this method:
Aᵣ = (mass of isotope 1 × abundance of isotope 1) + (mass of isotope 2 × abundance of isotope 2) + ... ÷ total abundance
If abundances are given as percentages, the total abundance is 100.
Chlorine has two isotopes:
Calculation:
Aᵣ = (35 × 75) + (37 × 25) ÷ 100
Aᵣ = (2625 + 925) ÷ 100
Aᵣ = 3550 ÷ 100
Aᵣ = 35.5
This is why the periodic table shows chlorine's relative atomic mass as 35.5.
Copper has two isotopes:
Calculation:
Aᵣ = (63 × 69) + (65 × 31) ÷ 100
Aᵣ = (4347 + 2015) ÷ 100
Aᵣ = 6362 ÷ 100
Aᵣ = 63.62
The periodic table shows copper's Aᵣ as approximately 63.5.
Magnesium has three isotopes:
Calculation:
Aᵣ = (24 × 79) + (25 × 10) + (26 × 11) ÷ 100
Aᵣ = (1896 + 250 + 286) ÷ 100
Aᵣ = 2432 ÷ 100
Aᵣ = 24.32
The periodic table shows magnesium's Aᵣ as approximately 24.3.
Exam Tip: Always show your working clearly in calculations. Even if you get the final answer wrong, you can still earn marks for your method. Remember to divide by the total abundance (usually 100 if given as percentages).
If the relative atomic mass of an element is close to one isotope's mass number, that isotope must be the most abundant:
Mass spectrometry is the technique used to determine the isotopic composition of an element — that is, which isotopes exist and their relative abundance. A mass spectrometer:
Subscribe to continue reading
Get full access to this lesson and all 10 lessons in this course.