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This lesson covers moments, levers, and gears as required by the AQA GCSE Physics specification (4.5.5). This is Higher Tier only content. A moment is the turning effect of a force. Understanding moments is essential for explaining how levers, gears, and other rotating systems work in everyday life and in engineering.
A moment is the turning effect of a force about a pivot (also called a fulcrum). When you push a door handle, turn a spanner, or use a see-saw, you are applying a moment.
The moment of a force is calculated using:
M = F x d
Where:
Key points:
| Quantity | Value | Unit |
|---|---|---|
| Force applied to a spanner | 20 N | N |
| Distance from pivot | 0.3 m | m |
| Moment | 20 x 0.3 = 6 | Nm |
Exam Tip: Always use the perpendicular distance in the moment equation. If the force is applied at an angle, the perpendicular distance is shorter than the actual distance from the pivot. This is a common source of errors in exam calculations.
The principle of moments states:
When an object is in equilibrium (balanced), the sum of the clockwise moments about any pivot equals the sum of the anticlockwise moments about that pivot.
In equation form:
Sum of clockwise moments = Sum of anticlockwise moments
F1 x d1 = F2 x d2
This principle applies to any balanced system — see-saws, beams, levers, and many other situations.
A child of weight 400 N sits 2.0 m from the pivot of a see-saw. Where must a child of weight 500 N sit to balance the see-saw?
Using the principle of moments:
Clockwise moment = Anticlockwise moment
500 x d2 = 400 x 2.0
500 x d2 = 800
d2 = 800 / 500
d2 = 1.6 m from the pivot
graph LR
subgraph "Balanced See-Saw"
A["400 N"] ---|"2.0 m"| P["Pivot"]
P ---|"1.6 m"| B["500 N"]
end
style P fill:#e67e22,color:#fff
style A fill:#2980b9,color:#fff
style B fill:#e74c3c,color:#fff
Exam Tip: When solving moment problems, always clearly identify the pivot point first. Then work out which forces cause clockwise moments and which cause anticlockwise moments. Set them equal and solve. Show all your working clearly for full marks.
A force of 15 N is applied to a door handle at a perpendicular distance of 0.8 m from the hinge (pivot).
M = F x d M = 15 x 0.8 M = 12 Nm
A moment of 24 Nm is needed to turn a bolt. The spanner is 0.4 m long. What force is needed?
M = F x d 24 = F x 0.4 F = 24 / 0.4 F = 60 N
A uniform beam of length 4.0 m is balanced on a pivot at its centre. A 60 N weight is placed 1.5 m from the pivot on the left side. What weight must be placed 1.0 m from the pivot on the right side to balance the beam?
Clockwise moment = Anticlockwise moment W x 1.0 = 60 x 1.5 W x 1.0 = 90 W = 90 N
A lever is a simple machine that uses a pivot (fulcrum) to multiply the effect of a force. Levers make it easier to do work by either:
A lever works by applying a small force at a large distance from the pivot to produce a large force at a small distance from the pivot (or vice versa).
The principle of moments explains why:
If F1 x d1 = F2 x d2, then a small force (F1) at a large distance (d1) can balance a large force (F2) at a small distance (d2).
| Class | Arrangement | Example |
|---|---|---|
| Class 1 | Pivot between effort and load | See-saw, crowbar, scissors |
| Class 2 | Load between pivot and effort | Wheelbarrow, nutcracker, bottle opener |
| Class 3 | Effort between pivot and load | Tweezers, fishing rod, human forearm |
graph LR
subgraph "Class 1 Lever"
E1["Effort"] ---|"d1"| P1["Pivot"] ---|"d2"| L1["Load"]
end
subgraph "Class 2 Lever"
P2["Pivot"] ---|"d2"| L2["Load"] ---|"d1"| E2["Effort"]
end
subgraph "Class 3 Lever"
P3["Pivot"] ---|"d1"| E3["Effort"] ---|"d2"| L3["Load"]
end
style P1 fill:#e67e22,color:#fff
style P2 fill:#e67e22,color:#fff
style P3 fill:#e67e22,color:#fff
style E1 fill:#2980b9,color:#fff
style E2 fill:#2980b9,color:#fff
style E3 fill:#2980b9,color:#fff
style L1 fill:#e74c3c,color:#fff
style L2 fill:#e74c3c,color:#fff
style L3 fill:#e74c3c,color:#fff
Exam Tip: [H] You may be asked to explain how a lever acts as a force multiplier. State that the effort is applied at a large distance from the pivot, and the principle of moments means a smaller effort force can balance a larger load force. Use M = F x d to support your explanation.
Gears are toothed wheels that mesh (interlock) together. When one gear turns, it causes the other gear to turn. Gears are used to:
The moment transmitted by a gear depends on the radius of the gear:
M = F x r
Where r is the radius of the gear.
If a small gear (small radius) drives a large gear (large radius):
If a large gear drives a small gear:
| Driving Gear | Driven Gear | Effect on Force | Effect on Speed | Direction |
|---|---|---|---|---|
| Small | Large | Force multiplied | Speed reduced | Reversed |
| Large | Small | Force reduced | Speed multiplied | Reversed |
| Same size | Same size | No change | No change | Reversed |
graph LR
subgraph "Gear System"
SG["Small gear (fast, low force)"] -->|"Meshes with"| LG["Large gear (slow, high force)"]
end
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